ac67d10050
Properly mark loop as diverging if it has no breaks Due to specifics about the desugaring of the `.await` operator, HIR typeck doesn't recognize that `.await`ing an `impl Future<Output = !>` will diverge in the same way as calling a `fn() -> !`. This is because the await operator desugars to approximately: ```rust loop { match future.poll(...) { Poll::Ready(x) => break x, Poll::Pending => {} } } ``` We know that the value of `x` is `!`, however since `break` is a coercion site, we coerce `!` to some `?0` (the type of the loop expression). Then since the type of the `loop {...}` expression is `?0`, we will not detect the loop as diverging like we do with other expressions that evaluate to `!`: |
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This is the main source code repository for Rust. It contains the compiler, standard library, and documentation.
Why Rust?
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Performance: Fast and memory-efficient, suitable for critical services, embedded devices, and easily integrate with other languages.
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Reliability: Our rich type system and ownership model ensure memory and thread safety, reducing bugs at compile-time.
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Productivity: Comprehensive documentation, a compiler committed to providing great diagnostics, and advanced tooling including package manager and build tool (Cargo), auto-formatter (rustfmt), linter (Clippy) and editor support (rust-analyzer).
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Read "Installation" from The Book.
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