rust/tests/ui/binding/irrefutable-if-let-without-else.rs
Esteban Küber a939bad513 Suggest turnging if let into irrefutable let if appropriate
When encountering an `if let` tail expression without an `else` arm for an
enum with a single variant, suggest writing an irrefutable `let` binding
instead.

```
error[E0317]: `if` may be missing an `else` clause
  --> $DIR/irrefutable-if-let-without-else.rs:8:5
   |
LL |   fn foo(x: Enum) -> i32 {
   |                      --- expected `i32` because of this return type
LL | /     if let Enum::Variant(value) = x {
LL | |         value
LL | |     }
   | |_____^ expected `i32`, found `()`
   |
   = note: `if` expressions without `else` evaluate to `()`
   = help: consider adding an `else` block that evaluates to the expected type
help: consider using an irrefutable `let` binding instead
   |
LL ~     let Enum::Variant(value) = x;
LL ~         value
   |
```

Fix #61788.
2024-02-06 03:53:06 +00:00

29 lines
620 B
Rust

// run-rustfix
enum Enum {
Variant(i32),
}
struct Struct(i32);
fn foo(x: Enum) -> i32 {
if let Enum::Variant(value) = x { //~ ERROR `if` may be missing an `else` clause
value
}
}
fn bar(x: Enum) -> i32 {
if let Enum::Variant(value) = x { //~ ERROR `if` may be missing an `else` clause
let x = value + 1;
x
}
}
fn baz(x: Struct) -> i32 {
if let Struct(value) = x { //~ ERROR `if` may be missing an `else` clause
let x = value + 1;
x
}
}
fn main() {
let _ = foo(Enum::Variant(42));
let _ = bar(Enum::Variant(42));
let _ = baz(Struct(42));
}