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When going through auto-deref, the `<T as Clone>` impl sometimes needs to be specified for rustc to actually clone the value and not the reference. ``` error[E0507]: cannot move out of dereference of `S` --> $DIR/needs-clone-through-deref.rs:15:18 | LL | for _ in self.clone().into_iter() {} | ^^^^^^^^^^^^ ----------- value moved due to this method call | | | move occurs because value has type `Vec<usize>`, which does not implement the `Copy` trait | note: `into_iter` takes ownership of the receiver `self`, which moves value --> $SRC_DIR/core/src/iter/traits/collect.rs:LL:COL help: you can `clone` the value and consume it, but this might not be your desired behavior | LL | for _ in <Vec<usize> as Clone>::clone(&self.clone()).into_iter() {} | ++++++++++++++++++++++++++++++ + ``` CC #109429.
22 lines
747 B
Plaintext
22 lines
747 B
Plaintext
error[E0507]: cannot move out of `*foo` which is behind a shared reference
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--> $DIR/suggest-clone.rs:10:5
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LL | foo.foo();
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| ^^^ ----- `*foo` moved due to this method call
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| move occurs because `*foo` has type `Foo`, which does not implement the `Copy` trait
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note: `Foo::foo` takes ownership of the receiver `self`, which moves `*foo`
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--> $DIR/suggest-clone.rs:6:12
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LL | fn foo(self) {}
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| ^^^^
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help: you can `clone` the value and consume it, but this might not be your desired behavior
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LL | <Foo as Clone>::clone(&foo).foo();
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| +++++++++++++++++++++++ +
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error: aborting due to 1 previous error
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For more information about this error, try `rustc --explain E0507`.
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