mirror of
https://github.com/rust-lang/rust.git
synced 2024-11-23 15:23:46 +00:00
075a6bbef9
No existing test failed if the [`panic!()`][1] of the `println!()`
family of functions was removed, or if its message was changed.
So add such a test.
[1] 104f4300cf/library/std/src/io/stdio.rs (L1007-L1009)
45 lines
1.3 KiB
Rust
45 lines
1.3 KiB
Rust
// run-pass
|
|
// check-run-results
|
|
// ignore-windows
|
|
// ignore-emscripten
|
|
// ignore-fuchsia
|
|
// ignore-horizon
|
|
// ignore-android
|
|
// normalize-stderr-test ".rs:\d+:\d+" -> ".rs:LL:CC"
|
|
|
|
// Test what the error message looks like when `println!()` panics because of
|
|
// `std::io::ErrorKind::BrokenPipe`
|
|
|
|
#![feature(unix_sigpipe)]
|
|
|
|
use std::env;
|
|
use std::process::{Command, Stdio};
|
|
|
|
#[unix_sigpipe = "sig_ign"]
|
|
fn main() {
|
|
let mut args = env::args();
|
|
let me = args.next().unwrap();
|
|
|
|
if let Some(arg) = args.next() {
|
|
// More than enough iterations to fill any pipe buffer. Normally this
|
|
// loop will end with a panic more or less immediately.
|
|
for _ in 0..65536 * 64 {
|
|
println!("{arg}");
|
|
}
|
|
unreachable!("should have panicked because of BrokenPipe");
|
|
}
|
|
|
|
// Set up a pipeline with a short-lived consumer and wait for it to finish.
|
|
// This will produce the `println!()` panic message on stderr.
|
|
let mut producer = Command::new(&me)
|
|
.arg("this line shall appear exactly once on stdout")
|
|
.env("RUST_BACKTRACE", "0")
|
|
.stdout(Stdio::piped())
|
|
.spawn()
|
|
.unwrap();
|
|
let mut consumer =
|
|
Command::new("head").arg("-n1").stdin(producer.stdout.take().unwrap()).spawn().unwrap();
|
|
consumer.wait().unwrap();
|
|
producer.wait().unwrap();
|
|
}
|