rust/tests/ui/borrowck/clone-span-on-try-operator.stderr
Esteban Küber 03c88aaf21 Tweak .clone() suggestion to work in more cases
When going through auto-deref, the `<T as Clone>` impl sometimes needs
to be specified for rustc to actually clone the value and not the
reference.

```
error[E0507]: cannot move out of dereference of `S`
  --> $DIR/needs-clone-through-deref.rs:15:18
   |
LL |         for _ in self.clone().into_iter() {}
   |                  ^^^^^^^^^^^^ ----------- value moved due to this method call
   |                  |
   |                  move occurs because value has type `Vec<usize>`, which does not implement the `Copy` trait
   |
note: `into_iter` takes ownership of the receiver `self`, which moves value
  --> $SRC_DIR/core/src/iter/traits/collect.rs:LL:COL
help: you can `clone` the value and consume it, but this might not be your desired behavior
   |
LL |         for _ in <Vec<usize> as Clone>::clone(&self.clone()).into_iter() {}
   |                  ++++++++++++++++++++++++++++++            +
```

CC #109429.
2023-12-04 21:54:32 +00:00

22 lines
785 B
Plaintext

error[E0507]: cannot move out of `*foo` which is behind a shared reference
--> $DIR/clone-span-on-try-operator.rs:10:5
|
LL | (*foo).foo();
| ^^^^^^ ----- `*foo` moved due to this method call
| |
| move occurs because `*foo` has type `Foo`, which does not implement the `Copy` trait
|
note: `Foo::foo` takes ownership of the receiver `self`, which moves `*foo`
--> $DIR/clone-span-on-try-operator.rs:6:12
|
LL | fn foo(self) {}
| ^^^^
help: you can `clone` the value and consume it, but this might not be your desired behavior
|
LL | <Foo as Clone>::clone(&(*foo)).foo();
| +++++++++++++++++++++++ +
error: aborting due to 1 previous error
For more information about this error, try `rustc --explain E0507`.