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stdlib: Make merge_sort take [mutable? T]
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@ -20,7 +20,7 @@ Merge sort. Returns a new vector containing the sorted list.
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Has worst case O(n log n) performance, best case O(n), but
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is not space efficient. This is a stable sort.
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*/
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fn merge_sort<T>(le: lteq<T>, v: [T]) -> [T] {
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fn merge_sort<T>(le: lteq<T>, v: [mutable? T]) -> [T] {
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fn merge<T>(le: lteq<T>, a: [T], b: [T]) -> [T] {
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let rs: [T] = [];
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let a_len: uint = len::<T>(a);
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@ -38,7 +38,8 @@ fn merge_sort<T>(le: lteq<T>, v: [T]) -> [T] {
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ret rs;
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}
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let v_len: uint = len::<T>(v);
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if v_len <= 1u { ret v; }
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if v_len == 0u { ret []; }
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if v_len == 1u { ret [v[0]]; }
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let mid: uint = v_len / 2u;
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let a: [T] = slice::<T>(v, 0u, mid);
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let b: [T] = slice::<T>(v, mid, v_len);
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@ -26,3 +26,11 @@ fn test() {
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check_sort(v1, v2);
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}
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}
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#[test]
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fn test_merge_sort_mutable() {
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fn lteq(&&a: int, &&b: int) -> bool { ret a <= b; }
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let v1 = [mutable 3, 2, 1];
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let v2 = std::sort::merge_sort(lteq, v1);
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assert v2 == [1, 2, 3];
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}
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