Switching out range(0,10) example to 0..10. Tests fine

This commit is contained in:
Erick Rivas 2015-01-11 02:15:29 -06:00
parent 431105a70a
commit 8e42f1e6c3

View File

@ -18,7 +18,7 @@ for (x = 0; x < 10; x++) {
Instead, it looks like this:
```{rust}
for x in range(0, 10) {
for x in 0..10 {
println!("{}", x); // x: i32
}
```
@ -38,7 +38,7 @@ valid for the loop body. Once the body is over, the next value is fetched from
the iterator, and we loop another time. When there are no more values, the
`for` loop is over.
In our example, `range` is a function that takes a start and an end position,
In our example, `0..10` is an expression that takes a start and an end position,
and gives an iterator over those values. The upper bound is exclusive, though,
so our loop will print `0` through `9`, not `10`.
@ -123,7 +123,7 @@ We now loop forever with `loop` and use `break` to break out early.
iteration. This will only print the odd numbers:
```{rust}
for x in range(0, 10) {
for x in 0..10 {
if x % 2 == 0 { continue; }
println!("{}", x);