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Do not check twice whether qpath
is a QPath::TypeRelative
variant
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parent
646b28f5f6
commit
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@ -108,18 +108,16 @@ fn parse_call(cx: &LateContext<'_>, span: Span, func: &Expr<'_>, args: &[Expr<'_
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let arg_kind = &args[0].kind;
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if let ExprKind::Path(qpath) = &func.kind {
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if let QPath::TypeRelative(_, _) = qpath {
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// String::from(...) or String::try_from(...)
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if let QPath::TypeRelative(ty, path_seg) = qpath
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&& [sym::from, sym::try_from].contains(&path_seg.ident.name)
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&& let TyKind::Path(qpath) = &ty.kind
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&& let QPath::Resolved(_, path) = qpath
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&& let [path_seg] = path.segments
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&& path_seg.ident.name == sym::String
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&& is_expr_kind_empty_str(arg_kind)
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{
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warn_then_suggest(cx, span);
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}
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// String::from(...) or String::try_from(...)
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if let QPath::TypeRelative(ty, path_seg) = qpath
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&& [sym::from, sym::try_from].contains(&path_seg.ident.name)
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&& let TyKind::Path(qpath) = &ty.kind
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&& let QPath::Resolved(_, path) = qpath
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&& let [path_seg] = path.segments
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&& path_seg.ident.name == sym::String
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&& is_expr_kind_empty_str(arg_kind)
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{
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warn_then_suggest(cx, span);
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} else if let QPath::Resolved(_, path) = qpath {
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// From::from(...) or TryFrom::try_from(...)
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if let [path_seg1, path_seg2] = path.segments
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