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ruby: add a new .dev output to ruby derivations
The idea is to bundle ruby, bundler and bundix together. I was having issues where bundler was installed with ruby 2.3.0 and I wanted to use ruby 2.0.0. With this change all the developer has to do is install `ruby_2_0_0.dev` either in his environment or in a nix-shell.
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@ -1,6 +1,7 @@
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{ stdenv, lib, fetchurl, fetchFromSavannah, fetchFromGitHub
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, zlib, openssl, gdbm, ncurses, readline, groff, libyaml, libffi, autoreconfHook, bison
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, autoconf, darwin ? null
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, buildEnv, bundler, bundix
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} @ args:
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let
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@ -35,6 +36,7 @@ let
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, libffi, fiddleSupport ? true
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, autoreconfHook, bison, autoconf
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, darwin ? null
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, buildEnv, bundler, bundix
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}:
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let rubySrc =
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if useRailsExpress then fetchFromGitHub {
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@ -146,11 +148,15 @@ let
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};
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passthru = rec {
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inherit majorVersion minorVersion teenyVersion patchLevel;
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inherit majorVersion minorVersion teenyVersion patchLevel version;
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rubyEngine = "ruby";
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baseRuby = baseruby;
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libPath = "lib/${rubyEngine}/${versionNoPatch}";
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gemPath = "lib/${rubyEngine}/gems/${versionNoPatch}";
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dev = import ./dev.nix {
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inherit buildEnv bundler bundix;
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ruby = self;
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};
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};
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}
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) args; in self;
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24
pkgs/development/interpreters/ruby/dev.nix
Normal file
24
pkgs/development/interpreters/ruby/dev.nix
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@ -0,0 +1,24 @@
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/* An environment for development that bundles ruby, bundler and bundix
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together. This avoids version conflicts where each is using a diferent
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version of each-other.
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*/
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{ buildEnv, ruby, bundler, bundix }:
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let
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bundler_ = bundler.override {
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ruby = ruby;
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};
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bundix_ = bundix.override {
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ruby = ruby;
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bundler = bundler_;
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};
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in
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buildEnv {
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name = "${ruby.rubyEngine}-dev-${ruby.version}";
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paths = [
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bundix_
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bundler_
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ruby
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];
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pathsToLink = [ "/bin" ];
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ignoreCollisions = true;
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}
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